JEE Mains · Maths · STD 11 - 12. limits
For each \(t \in R\), let \([t]\) be the greatest integer less than or equal to \(t\). Then \(\mathop {\lim }\limits_{x \to 1 + } \,\frac{{\left( {1 - \left| x \right| + \sin \left| {1 + x} \right|} \right)\,\sin \,\left( {\frac{\pi }{2}\,\left[ {1 - x} \right]} \right)}}{{\left| {1 - x} \right|\left| {1 - x} \right|}}\)
- A equals \(1\)
- B equals \(0\)
- C equals \(-1\)
- D does not exist
Answer & Solution
Correct Answer
(B) equals \(0\)
Step-by-step Solution
Detailed explanation
\(\mathop {\lim }\limits_{x \to 1 + } \frac{{\left( {1 - \left| x \right| + \sin \left| {1 - x} \right|} \right)\sin \left( {\left[ {1 - x} \right]\frac{\pi }{2}} \right)}}{{\left| {1 - x} \right|\left[ {1 - x} \right]}}\)…
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