JEE Mains · Maths · STD 12 - 11. three dimension geometry
The square of the distance of the image of the point \((6,1,5)\) in the line \(\frac{x-1}{3}=\frac{y}{2}=\frac{z-2}{4}\), from the origin is .............
- A \(75\)
- B \(32\)
- C \(62\)
- D \(35\)
Answer & Solution
Correct Answer
(C) \(62\)
Step-by-step Solution
Detailed explanation
\( \text { Let } \mathrm{M}(3 \lambda+1,2 \lambda, 4 \lambda+2) \) \( \overrightarrow{\mathrm{AM}} \cdot \overrightarrow{\mathrm{b}}=0 \) \( \Rightarrow \quad 9 \lambda-15+4 \lambda-2+16 \lambda-12=0 \) \( \Rightarrow \quad 29 \lambda=29 \) \( \Rightarrow \quad \lambda=1 \)…
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