JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
Let \(A B\) be a chord of length \(12\) of the circle \((x-2)^{2}+(y+1)^{2}=\frac{169}{4}\) If tangents drawn to the circle at points \(A\) and \(B\) intersect at the point \(P\), then five times the distance of point \(P\) from chord \(AB\) is equal to\(.......\)
- A \(71\)
- B \(73\)
- C \(72\)
- D \(74\)
Answer & Solution
Correct Answer
(C) \(72\)
Step-by-step Solution
Detailed explanation
\(\cos \theta=\frac{6}{\frac{13}{2}}=\frac{12}{13}\) \(\sin \theta=\frac{5}{13}\) \(PM = AM \cot \theta\) \(PM =6\left(\frac{12}{5}\right) \therefore 5( PM )=72\)
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