JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
When an electric current is passes through acidified water, \(112\,mL\) of hydrogen gas at \(N. T.P\). was collected at the cathode in \(965\,seconds\). The current passed, in ampere, is
- A \(2.0\)
- B \(0.1\)
- C \(0.5\)
- D \(1.0\)
Answer & Solution
Correct Answer
(D) \(1.0\)
Step-by-step Solution
Detailed explanation
Reduction at cathode: \(2{e^ - }\, + \,2{H_2}O\, \to \,{H_2}\, + \,2O{H^ - }\) (valence factor) \(H_2=2\) At \(NTP\) \(22400\,mL\) of \(H_2=1\,mole\) of \(H_2\,\,112\,mL\) of \({H_2}\, = \,\frac{1}{{22400}}\, \times \,112\, = \,0.005\,mole\) of \(H_2\) Moles of \(H_2\) produced…
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