JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
\(FeO _4^{2-} \stackrel{+2.2\,V }{\longrightarrow} Fe ^{3+} \stackrel{+0.70\,V }{\longrightarrow} Fe ^{2+} \stackrel{-0.45\,V }{\longrightarrow} Fe ^0\) \(E _{ FeO _4^{2-} / Fe ^{2+}}^\theta\) is \(x \times 10^{-3} V\). The value of \(x\) is \(.........\).
- A \(1824\)
- B \(1825\)
- C \(1823\)
- D \(1822\)
Answer & Solution
Correct Answer
(B) \(1825\)
Step-by-step Solution
Detailed explanation
\(4 \times E =3 \times 2.2+1 \times 0.7\) \(E =\frac{7.3}{4}=1.825 V =1825 \times 10^{-3}\,V\)
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