JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Two solutions \(A\) and \(B\) are prepared by dissolving \(1\,g\) of non-volatile solutes \(X\) and \(Y\). respectively in \(1\,kg\) of water. The ratio of depression in freezing points for \(A\) and \(B\) is found to be \(1: 4\). The ratio of molar masses of \(X\) and \(Y\) is.
- A \(1: 4\)
- B \(1: 0.25\)
- C \(1: 0.20\)
- D \(1: 5\)
Answer & Solution
Correct Answer
(B) \(1: 0.25\)
Step-by-step Solution
Detailed explanation
\(\frac{\Delta T _{ ex }}{\Delta T _{ fy }}=\frac{ k _{ f } \cdot m _{ x }}{ k _{ f } \cdot m _{ y }}=\frac{\frac{1 / M _{ x }}{1 / M _{ y }}}{\frac{1}{1}}\) \(\frac{1}{4}=\frac{M_{y}}{M_{x}}\) \(M _{ x }: M _{ y }=1: 0.25\)
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