JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
When \(5\) moles of \(He\) gas expand isothermally and reversibly at \(300 \,K\) from \(10\, litre\) to \(20 \,litre,\) the magnitude of the maximum work obtained is \(.......\,J\). [nearest integer] (Given: \(R =8.3 \,J \,K ^{-1} \,mol ^{-1}\) and \(\log 2=0.3010\) )
- A \(6574\)
- B \(1245\)
- C \(9130\)
- D \(8630\)
Answer & Solution
Correct Answer
(D) \(8630\)
Step-by-step Solution
Detailed explanation
\(n =5 \,mol\) \(T =300\, K\) \(V _{1}=10\, L\) \(V _{2}=20 \,L\) \(W =- nRT \ell n \frac{ V _{2}}{ V _{1}}\) \(=-5 \times 8.3 \times 300 \times \ell n \frac{20}{10}\) \(=-8630.38\, J\)
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