JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
Two sources of light emit X-rays of wavelength \(1\, nm\) and visible light of wavelength \(500\, nm ,\) respectively. Both the sources emit light of the same power \(200\, W\). The ratio of the number density of photons of X-rays to the number densitty of photons of the visible light of the given wavelengths is
- A \(\frac{1}{500}\)
- B \(500\)
- C \(250\)
- D \(\frac{1}{250}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{500}\)
Step-by-step Solution
Detailed explanation
\(P=\frac{n h c}{\lambda t}\) \(\therefore \frac{n_{1}}{n_{2}}=\frac{\lambda_{1}}{\lambda_{2}}=\frac{1}{5}\)
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