JEE Mains · Chemistry · STD 11 - 2. structure of atom
The wavelength of an electron and a neutron will become equal when the velocity of the electron is \(x\) times the velocity of neutron. The value of \(x\) is (Nearest Integer)(Mass of electron is \(9.1 \times 10^{-31} kg\) and mass of neutron is \(1.6 \times 10^{-27}\,kg\) )
- A \(1757\)
- B \(1758\)
- C \(1756\)
- D \(1755\)
Answer & Solution
Correct Answer
(B) \(1758\)
Step-by-step Solution
Detailed explanation
\(v_{e}=x v_{N}\) \(\lambda_{ e }=\lambda_{ N }\) \(\Rightarrow \frac{ h }{ m _{ e } v _{ c }}=\frac{ h }{ m _{ N } v_{ N }}\) \(v_{ e }=\frac{ m _{ N }}{ m _{ e }} \cdot v _{ N }\) \(=\frac{1.6 \times 10^{-27}}{9.1 \times 10^{-31}} v_{ N }\) \(v_{ e }=1758.24 \times v_{ N }\)
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