JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
The vapour pressure of \(30 \% ( w / v )\) aqueous solution of glucose is \(......\,mm\,Hg\) at \(25^{\circ}\,C\).[Given : The density of \(30 \%\) (w/v), aqueous solution of glucose is \(1.2\,g\,cm ^{-3}\) and vapour pressure of pure water is \(24\,mm\,Hg\).](Molar mass of glucose is \(\left.180\,g\,mol ^{-1}.\right)\)
- A \(23\)
- B \(22\)
- C \(21\)
- D \(24\)
Answer & Solution
Correct Answer
(A) \(23\)
Step-by-step Solution
Detailed explanation
\(\frac{24- P _{ s }}{ P _{ s }}=\frac{ m \times 18}{1000}\) wt of solute \(=30\,gm\) Volume of solution \(=100\,mL\) wt. of solution \(=1.2 \times 100=120\,gm\) wt. of solvent \(=120-30=90\,gm\) \(m =\frac{30 \times 1000}{180 \times 90}=1.85\)…
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