JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
The solubility of \(N_2\) in water at \(300\,K\) and \(500\,torr\) partial pressure is \(0.01\,g\,L^{- 1}\) .The solubility ( in \(g\,L^{ -1}\))at \(750\,torr\) partial pressure is
- A \(0.0075\)
- B \(0.005\)
- C \(0.02\)
- D \(0.015\)
Answer & Solution
Correct Answer
(D) \(0.015\)
Step-by-step Solution
Detailed explanation
According to Henry law \(\frac {P_1}{P_2}\,=\,\frac {S_1}{S_2}\) \(\frac {500}{750}\,=\,\frac {0.01}{S_2}\) \(\therefore \) \(=\,\frac {750\times 0.01}{500}\) \(=\,0.015\,g/L\)
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