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JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization

The transformation occurring in Duma's method is given below : \(\mathrm{C}_{2} \mathrm{H}_{7} \mathrm{~N}+\left(2 \mathrm{x}+\frac{\mathrm{y}}{2}\right) \mathrm{CuO} \rightarrow \mathrm{x\,CO}_{2}+\frac{y}{2} \mathrm{H}_{2} \mathrm{O}+\frac{\mathrm{z}}{2} \mathrm{~N}_{2}+\left(2\, \mathrm{x}+\frac{\mathrm{y}}{2}\right) \mathrm{Cu}\) The value of \(y\) is ...... .(Integer answer)

  1. A \(2\)
  2. B \(7\)
  3. C \(1\)
  4. D \(15\)
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Answer & Solution

Correct Answer

(B) \(7\)

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Detailed explanation

\mathrm{C}_{2} \mathrm{H}_{7} \mathrm{~N}+\left(2 \mathrm{x}+\frac{\mathrm{y}}{2}\right) \mathrm{CuO} \rightarrow \mathrm{x} \mathrm{CO}_{2}+\frac{\mathrm{y}}{2} \mathrm{H}_{2} \mathrm{O}+\frac{\mathrm{z}}{2} \mathrm{~N}_{2}+\left(2 \mathrm{x}+\frac{\mathrm{y}}{2}\right)…

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