JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
At \(25^{\circ} C , 50\, g\) of iron reacts with \(HCl\) to form \(FeCl _{2}\). The evolved hydrogen gas expands against a constant pressure of \(1\, bar.\) The work done by the gas during this expansion is ....... \(J.\) (Round off to the Nearest Integer) [Given : \(R =8.314 \,J mol ^{-1} K ^{-1}\). Assume,
hydrogen is an ideal gas] [Atomic mass off \(Fe\) is \(55.85\, u\) ]
- A \(2218\)
- B \(2222\)
- C \(2988\)
- D \(3418\)
Answer & Solution
Correct Answer
(A) \(2218\)
Step-by-step Solution
Detailed explanation
\(T =298 \,K , R =8.314\, \frac{ J }{ molK }\) \(\rightarrow\) Chemical reaction is \(Fe +2 HCl \rightarrow FeCl _{2}+ H _{2}( g )\) \(50\,g\) \(\quad\quad\quad\quad P =1\, bar\) \(=\frac{50}{55.85} \,mol\) \(\rightarrow\) Work done for \(1 \,mol\) gas…
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