JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
The resistance of a conductivity cell with cell constant \(1.14 \,\mathrm{~cm}^{-1}\), containing \(0.001\, \mathrm{M}\, \mathrm{KCl}\) at \(298\, \mathrm{~K}\) is \(1500 \,\Omega\). The molar conductivity of \(0.001\, \mathrm{M}\, \mathrm{KCl}\) solution at \(298\, \mathrm{~K}\) in \(\mathrm{S} \,\mathrm{cm}^{2}\, \mathrm{~mol}^{-1}\) is ...... . (Integer answer)
- A \(760\)
- B \(76\)
- C \(7.6\)
- D \(141\)
Answer & Solution
Correct Answer
(A) \(760\)
Step-by-step Solution
Detailed explanation
\(\mathrm{K}=\frac{1}{\mathrm{R}} \times \ell / \mathrm{A}=\left(\left(\frac{1}{1500}\right) \times 1.14\right)\, \mathrm{S}\, \mathrm{cm}^{-1}\)…
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