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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

The resistance of a conductivity cell with cell constant \(1.14 \,\mathrm{~cm}^{-1}\), containing \(0.001\, \mathrm{M}\, \mathrm{KCl}\) at \(298\, \mathrm{~K}\) is \(1500 \,\Omega\). The molar conductivity of \(0.001\, \mathrm{M}\, \mathrm{KCl}\) solution at \(298\, \mathrm{~K}\) in \(\mathrm{S} \,\mathrm{cm}^{2}\, \mathrm{~mol}^{-1}\) is ...... . (Integer answer)

  1. A \(760\)
  2. B \(76\)
  3. C \(7.6\)
  4. D \(141\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(760\)

Step-by-step Solution

Detailed explanation

\(\mathrm{K}=\frac{1}{\mathrm{R}} \times \ell / \mathrm{A}=\left(\left(\frac{1}{1500}\right) \times 1.14\right)\, \mathrm{S}\, \mathrm{cm}^{-1}\)…
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