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JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism

An electron with kinetic energy \(5 \mathrm{eV}\) enters a region of uniform magnetic field of \(3 \mu \mathrm{T}\) perpendicular to its direction. An electric field \(\mathrm{E}\) is applied perpendicular to the direction of velocity and magnetic field. electron moves along the same path, The value of \(\mathrm{E}\) is _______ \(\mathrm{NC}^{-1}\). (Given, mass of electron \(=9 \times 10^{-31} \mathrm{~kg}\), electric charge \(=1.6 \times 10^{-19} \mathrm{C}\) )

  1. A \(3\)
  2. B \(4\)
  3. C \(5\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4\)

Step-by-step Solution

Detailed explanation

For the given condition of moving undeflected, net force should be zero. \(\mathrm{qE} =\mathrm{qVB}\) \(\mathrm{E} =\mathrm{VB}\) \(=\sqrt{\frac{2 \times \mathrm{KE}}{\mathrm{m}}} \times \mathrm{B}\)…
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