JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
\(1\,g\) of non-volatile non-electrolyte solute is dissolved in \(100\,g\) of two different solvents \(A\) and \(B\) whose ebullioscopic constants are in the ratio of \(1 : 5.\) The ratio of the elevation in their boiling points, \(\frac{{\Delta \,{T_b}\,(A)}}{{\Delta \,{T_b}\,(B)}}\) is
- A \(5:1\)
- B \(10:1\)
- C \(1:5\)
- D \(1:0.2\)
Answer & Solution
Correct Answer
(C) \(1:5\)
Step-by-step Solution
Detailed explanation
\(\Delta \,{T_b}\, = \,{K_b}\, \times \,m\) \(\therefore \,\,\frac{{\Delta {T_{b\,(A)}}}}{{\Delta {T_{b\,(B)}}}}\, = \,\frac{{{K_{b(A)}}}}{{{K_{b(B)}}}}\) as \({m_A}\, = \,{m_B}\) \(\therefore \,\,\frac{{\Delta {T_{b\,(A)}}}}{{\Delta {T_{b\,(B)}}}}\, = \frac{1}{5}\)
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