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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
The rate constant of a zero order reaction is \(2.0\times10^{-2}\, mol\, L^{-1}\, s^{-1}\) . If the concentration of the reactant after \(25\, seconds\) is \(0.5\, M\). ......... \(M\) is the initial concentration.
- A \(0.5\)
- B \(1.25\)
- C \(12.5\)
- D \(1.0\)
Answer & Solution
Correct Answer
(D) \(1.0\)
Step-by-step Solution
Detailed explanation
For a zero order reaction Rate constant \( = \,k\, = \,\frac{{a - x}}{t}\) \(2\, \times \,{10^{ - 2}}\, = \,\frac{{a\, - \,0.5}}{{25}}\) \(a\, - \,0.5\, = \,0.5\) \(a\, = \,1.0\,M\)
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