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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

The rate constant of a zero order reaction is \(2.0\times10^{-2}\, mol\, L^{-1}\, s^{-1}\) . If the concentration of the reactant after \(25\, seconds\) is \(0.5\, M\). ......... \(M\) is the initial concentration.

  1. A \(0.5\)
  2. B \(1.25\)
  3. C \(12.5\)
  4. D \(1.0\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1.0\)

Step-by-step Solution

Detailed explanation

For a zero order reaction Rate constant \( = \,k\, = \,\frac{{a - x}}{t}\) \(2\, \times \,{10^{ - 2}}\, = \,\frac{{a\, - \,0.5}}{{25}}\) \(a\, - \,0.5\, = \,0.5\) \(a\, = \,1.0\,M\)
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