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JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2022
  • Easy
  • Numerical

The total internal energy of two mole monoatomic ideal gas at temperature \(T=300\,K\) will be ...........\(J\). \(\text { (Given } R =8.31\,J / mol.K )\)

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Answer & Solution

Correct Answer

(C) \(7479\)

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Detailed explanation

\(U = nC _{ v } T\)

\(=2 \times \frac{3}{2} R \times 300\)

\(=900 R =900 \times 8 \cdot 31=7479\,J\)

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