JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2022
- Easy
- Numerical
The total internal energy of two mole monoatomic ideal gas at temperature \(T=300\,K\) will be ...........\(J\). \(\text { (Given } R =8.31\,J / mol.K )\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(7479\)
Step-by-step Solution
Detailed explanation
\(U = nC _{ v } T\)
\(=2 \times \frac{3}{2} R \times 300\)
\(=900 R =900 \times 8 \cdot 31=7479\,J\)
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