JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
From the magnetic behaviour of \(\left[\mathrm{NiCl}_4\right]^{2-}\) (paramagnetic) and \(\left[\mathrm{Ni}(\mathrm{CO})_4\right]\) (diamagnetic), choose the correct geometry and oxidation state.
- A \(\left[\mathrm{NiCl}_4\right]^{2-}: \mathrm{Ni}^{\mathrm{II}}\), tetrahedral
\(\left[\mathrm{Ni}(\mathrm{CO})_4\right]: \mathrm{Ni}^{\mathrm{II}}\), square planar - B \(\left[\mathrm{NiCl}_4\right]^{2-}\) : \(\mathrm{Ni}^{\mathrm{II}}\), square planar
\(\left[\mathrm{Ni}(\mathrm{CO})_4\right]: \mathrm{Ni}(0)\), square planar - C \(\left[\mathrm{NiCl}_4\right]^{2-}: \mathrm{Ni}^{\mathrm{II}}\), tetrahedral
\(\left[\mathrm{Ni}(\mathrm{CO})_4\right]: \mathrm{Ni}(0)\), tetrahedral - D \(\left[\mathrm{NiCl}_4\right]^{2-}: \mathrm{Ni}(0)\), tetrahedral
\(\left[\mathrm{Ni}(\mathrm{CO})_4\right]: \mathrm{Ni}(0)\), square planar
Answer & Solution
Correct Answer
(C) \(\left[\mathrm{NiCl}_4\right]^{2-}: \mathrm{Ni}^{\mathrm{II}}\), tetrahedral
\(\left[\mathrm{Ni}(\mathrm{CO})_4\right]: \mathrm{Ni}(0)\), tetrahedral
Step-by-step Solution
Detailed explanation
\(\left[\mathrm{NiCl}_4\right]^{2-}\) \(\mathrm{Ni}^{+2}-[\mathrm{Ar}] 3 \mathrm{~d}^8 4 \mathrm{~s}^0 \rightarrow \mathrm{sp}^3\), Tetrahedral Number of unpaired electron \(=2\) paramagentic \(\left[\mathrm{Ni}(\mathrm{CO})_4\right]\)…
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