JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
A \(20.0 \,mL\) solution containing \(0.2 \,g\) impure \(H _{2} O _{2}\) reacts completely with \(0.316 \,g\) of \(KMnO _{4}\) in acid solution. The purity of \(H _{2} O _{2}(\) in \(\%)\) is........... (mol. wt. of \(H _{2} O _{2}=34 ;\) mol. wt. of \(\left. KMnO _{4}=158\right)\)
- A \(90\)
- B \(95\)
- C \(85\)
- D \(80\)
Answer & Solution
Correct Answer
(C) \(85\)
Step-by-step Solution
Detailed explanation
\(Eq\) of \(H _{2} O _{2}= Eq\) of \(KMnO _{4}\) \(x \times 2=\frac{0.316}{158} \times 5\) \(x=5 \times 10^{-3} mol\) \(m _{ H _{2} O _{2}}=5 \times 10^{-3} \times 34=0.17 gm\) \(\% H _{2} O _{2}=\frac{0.17}{0.2} \times 100=85\)
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