JEE Mains · Physics · STD 12 -7. Alternating current
The equation of current in a purely inductive circuit is \(5 \sin \left(49 \pi t-30^{\circ}\right)\). If the inductance is \(30\,mH\) then the equation for the voltage across the inductor, will be.\(\left\{\right.\) Let \(\left.\pi=\frac{22}{7}\right\}\)
- A \(1.47 \sin \left(49 \pi t -30^{\circ}\right)\)
- B \(1.47 \sin \left(49 \pi t+60^{\circ}\right)\)
- C \(23.1 \sin \left(49 \pi t -30^{\circ}\right)\)
- D \(23.1 \sin \left(49 \pi t+60^{\circ}\right)\)
Answer & Solution
Correct Answer
(D) \(23.1 \sin \left(49 \pi t+60^{\circ}\right)\)
Step-by-step Solution
Detailed explanation
\(v _{0}= i _{0} x _{ L }\) \(= i _{0}( wL )\) \(=(5)(49 \pi)\left(30 \times 10^{-3}\right)\) \(=23.1\) Voltage will lead current by \(90^{\circ}\). \(\therefore V =23.1 \sin \left(49 \pi t +60^{\circ}\right)\)
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