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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

At \(298\,K\), the standard reduction potential for \(Cu ^{2+} / Cu\) electrode is \(0.34\,V\). Given : \(K _{ sp } Cu ( OH )_2=1 \times 10^{-20}\) \(\operatorname{Take} \frac{2.303 RT }{ F }=0.059 \,V\) The reduction potential at \(pH =14\) for the above couple is \((-) x \times 10^{-2}\,V\). The value of \(x\) is \(........\).

  1. A \(24\)
  2. B \(23\)
  3. C \(22\)
  4. D \(25\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(25\)

Step-by-step Solution

Detailed explanation

\(Cu ( OH )_2( s ) \rightleftharpoons Cu ^{2+}( aq )+2 OH ^{-}( aq )\) \(Ksp =\left[ Cu ^{2+}\right]\left[ OH ^{-}\right]^2\) \(pH =14 ; pOH =0 ;\left[ OH ^{-}\right]=1\,M\) \({\left[ Cu ^{2+}\right]=\frac{ Ksp }{[1]^2}=10^{-20} M }\)…
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