JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
The magnetic moment is measured in Bohr Magneton (BM). Spin only magnetic moment of \(Fe\) in \(\left[ Fe \left( H _2 O \right)_6\right]^{3+}\) and \(\left[ Fe ( CN )_6\right]^{3-}\) complexes respectively is:
- A \(6.92\,B.M.\) in both
- B \(4.89\,B.M.\) and \(6.92\,B.M.\)
- C \(3.87\,B.M.\) and \(1.732\,B.M.\)
- D \(5.92\,B.M.\) and \(1.732\,B.M\)
Answer & Solution
Correct Answer
(D) \(5.92\,B.M.\) and \(1.732\,B.M\)
Step-by-step Solution
Detailed explanation
\(\left[ Fe \left( H _2 O \right)_6\right]^{3+}\) \(\therefore \text { Unpaired } e ^{-}=5\) \(\mu=\sqrt{ n ( n +2)}\) \(=\sqrt{5(5+2)}\) \(\mu=\sqrt{35}=5.92 \text { B.M. }\) \({\left[ Fe ( CN )_6\right]^{-3}}\) Pairing occur due to strong field ligand \(CN ^{-}\)…
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