JEE Mains · Chemistry · STD 12 - 9. Amines
Given below are two statements :
Statement I : One mole of propyne reacts with excess of sodium to liberate half a mole of \(\mathrm{H}_2\) gas.
Statement II : Four g of propyne reacts with \(\mathrm{NaNH}_2\) to liberate \(\mathrm{NH}_3\) gas which occupies 224 mL at STP.
In the light of the above statements, choose the most appropriate answer from the options given below:
- A Statement I is incorrect but Statement II is correct
- B Both Statement I and Statement II are correct
- C Statement I is correct but Statement II is incorrect
- D Both Statement I and Statement II are incorrect
Answer & Solution
Correct Answer
(C) Statement I is correct but Statement II is incorrect
Step-by-step Solution
Detailed explanation
\(\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CH}+\mathrm{Na} \rightarrow \mathrm{CH}_3-\mathrm{C} \equiv \mathrm{C}^{-} \mathrm{Na}^{+}+\frac{1}{2} \mathrm{H}_2\) Statement-l is correct. Moles of \(\mathrm{C}_3 \mathrm{H}_4=\frac{4}{40}=0.1\) mole…
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