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JEE Mains · Chemistry · STD 12 - p -Block elements - ll
The products obtained when chlorine gas reacts with cold and dilute aqueous \(NaOH\) are :
- A \(ClO^-\) and \(ClO_3^-\)
- B \(ClO_2^-\) and \(ClO_3^-\)
- C \(Cl^-\) and \(ClO^-\)
- D \(Cl^-\) and \(ClO_2^-\)
Answer & Solution
Correct Answer
(C) \(Cl^-\) and \(ClO^-\)
Step-by-step Solution
Detailed explanation
Dissolving the halogens in \(NaOH\) can in principle be used to make all the hypohalite ions. The reaction is \(\mathrm{Cl}_{2}+2 \mathrm{NaOH}(\mathrm{cold} / \mathrm{dilute}) \rightarrow \mathrm{NaCl}+\mathrm{NaOCl}+\mathrm{H}_{2} \mathrm{O}\)
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