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JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)

The \(\mathrm{K}_{\mathrm{sp}}\) for the following dissociation is \(1.6 \times 10^{-5}\) \(\mathrm{PbCl}_{2(\mathrm{s})} \rightleftharpoons \mathrm{Pb}_{(\mathrm{ag})}^{2+}+2 \mathrm{Cl}_{(\mathrm{aq})}^{-}\) Which of the following choices is correct for a mixture of \(300\; \mathrm{mL}\;\; 0.134 \;\mathrm{M} \;\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\) and \(100\; \mathrm{mL}\;\; 0.4\; \mathrm{M}\; \mathrm{NaCl} ?\)

  1. A \(\mathrm{Q} < \mathrm{K}_{\mathrm{sp}}\)
  2. B \(\mathrm{Q} > \mathrm{K}_{\mathrm{sp}}\)
  3. C \(\mathrm{Q} = \mathrm{K}_{\mathrm{sp}}\)
  4. D Not enough data provided
Verified Solution

Answer & Solution

Correct Answer

(B) \(\mathrm{Q} > \mathrm{K}_{\mathrm{sp}}\)

Step-by-step Solution

Detailed explanation

\(\left[\mathrm{Pb}^{2+}\right] =\frac{300 \times 0.134}{400}\) \(=1.005 \times 10^{-1} \mathrm{M}\) \(\left[\mathrm{C}^{-}\right] =\frac{100 \times 0.4}{400}\) \(=10^{-1} \mathrm{M}\)…
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