JEE Mains · Chemistry · STD 12 - 6. Haloalkanes and Haloarenes
The increasing order of the reactivity of the following halides for the \(S_N1\) reaction is \((I)\,\begin{array}{*{20}{c}}
{C{H_3}CHC{H_2}C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,} \\
{Cl\,\,\,\,\,\,\,\,\,}
\end{array}\) \((II)\,CH_3CH_2CH_2Cl\) \((III)\,H_3CO-C_6H_4-CH_2Cl\)
- A \((III) < (II) < (I)\)
- B \((II) < (I) < (III)\)
- C \((I) < (III) < (II)\)
- D \((II) < (III) < (I)\)
Answer & Solution
Correct Answer
(B) \((II) < (I) < (III)\)
Step-by-step Solution
Detailed explanation
Secondary, tertiary and benzylic halides appear to react by a mechanism that involves the formation of a carbocation and proceeds through \(\mathrm{S}_{\mathrm{N}} 1\) mechanism which takes place in two steps. The first step is the slow step \(-\) it is the rate-determining…
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