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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

The half-life period of a first order reaction is \(15\,minutes\). The amount of substance left after one hour will be

  1. A \(\frac{1}{4}\) of the original amount
  2. B \(\frac{1}{8}\) of the original amount
  3. C \(\frac{1}{16}\) of the original amount
  4. D \(\frac{1}{32}\) of the original amount
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{16}\) of the original amount

Step-by-step Solution

Detailed explanation

Given \(t_{1/2}\,=\,15\,minutes\) Total time \((T)\,=\,1\,hr\,=\,60\,min.\) From \(T\,=\,n\times t_{1/2}\) \(n\,=\,\frac {60}{15}\,=\,4\) Now from the formula \(\frac{N}{{{N_0}}}\, = \,{\left( {\frac{1}{2}} \right)^n}\)…
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