JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
The half life for the decomposition of gaseous compound \(A\) is \(240\,s\) when the gaseous pressure was \(500\,Torr\) initially. When the pressure was \(250\,Torr\), the half life was found to be \(4.0\,min\). The order of the reaction is....... (Nearest integer)
- A \(4\)
- B \(3\)
- C \(2\)
- D \(1\)
Answer & Solution
Correct Answer
(D) \(1\)
Step-by-step Solution
Detailed explanation
\(\left( t _{1 / 2}\right)_{500 \text { torr }}=240\,sec =4\,min\). \(\left( t _{1 / 2}\right)_{250 \text { torr }}=4\,min\) \(t _{1 / 2} \propto a ^{1- n }\) As \(t _{1 / 2}\) is independent of initial pressure. Hence, order is \(1^{st}\) order.
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