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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
The Gibbs energy for the decomposition of \(Al_2O_3\) at \(500\,^oC\) is as follows \(\frac{2}{3}A{l_2}{O_3} \to \frac{4}{3}Al + {O_2},{\Delta _r}G = + 940\,kJ\,mo{l^{ - 1}}\) The potential difference needed for the electrolytic reduction of aluminium oxide ............... \(\mathrm{V}\)
- A \(4.5\)
- B \(3\)
- C \(5\)
- D \(2.5\)
Answer & Solution
Correct Answer
(B) \(3\)
Step-by-step Solution
Detailed explanation
In the reaction \(\frac{2}{3}A{l_2}{O_3}\, \to \,\frac{4}{3}Al\, + \,{O_2}\) For the oxidation half - reaction \(A{l^{3 + }}\, + \,3{e^ - }\, \to \,Al\) no. of electron transfered \((n)=3\) \(\Delta G^o\,=\,-\,nFE^o\) \(940=3\times 96500 \times E^o\)…
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