JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
Given : \(E^o_{Cr^{3+}/Cr} =-0.74\, V,\,\) \(E^o_{MnO_4^-/Mn^{2+}} =1.51 \,V\) \(E^o_{Cr_2O_7^{2-}/Cr^3+} =1.33\,V:\) \(E^o_{Cl/Cl^-} =1.36\,V\) Based on the data given above, strongest oxidising agent will be :
- A \(Cl\)
- B \(Cr^{3+}\)
- C \(Mn^{2+}\)
- D \(MnO_4^-\)
Answer & Solution
Correct Answer
(D) \(MnO_4^-\)
Step-by-step Solution
Detailed explanation
Higher the value of standard reduction potential stronger will be the oxidising agent, hence \(M n O_{4}^-\) is the strongest oxidising agent.
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