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JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)

At \(1990\, K\) and \(1\, atm\) pressure, there are equal number of \(Cl _{2}\) molecules and \(Cl\) atoms in the reaction mixture. The value \(K _{ P }\) for the reaction \(Cl _{2( g )} \rightleftharpoons 2 \,Cl _{( g )}\) under the above conditions is \(x \times 10^{-1}\) The value of \(x\) is .......... (Rounded of to the nearest integer)

  1. A \(7\)
  2. B \(8\)
  3. C \(5\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(5\)

Step-by-step Solution

Detailed explanation

\(Cl _{2} \rightleftharpoons 2 Cl\) Let mol of both of \(Cl _{2}\) and \(Cl\) is \(x\) \(P _{ Cl }=\frac{ x }{2 x } \times 1=\frac{1}{2}\) \(P _{ Cl _{2}}=\frac{ x }{2 x } \times 1=\frac{1}{2}\)…
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