JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
Consider the following reaction \(\mathrm{A}+\mathrm{B} \rightarrow \mathrm{C}\) The time taken for \(A\) to become \(1 / 4^{\text {th }}\) of its inital concentration is twice the time taken to become \(1 / 2\) of the same. Also, when the change of concentration of \(B\) is plotted against time, the resulting graph gives a straight line with a negative slope and a positive intercept on the concentration axis. The overall order of the reaction is _______.
- A \(5\)
- B \(4\)
- C \(3\)
- D \(1\)
Answer & Solution
Correct Answer
(D) \(1\)
Step-by-step Solution
Detailed explanation
For \(1^{\text {st }}\) order reaction \(75 \% \text { life }=2 \times 50 \% \text { life }\) So order with respect to \(A\) will be first order. So order with respect to \(B\) will be zero. Overall order of reaction \(=1+0=1\)
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