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JEE Mains · Chemistry · STD 11 - 2. structure of atom
The de Broglie wavelength of a car of mass \(1000\, kg\) and velocity \(36\, km/hr\) is
- A \(6.626\times10^{-34}\, m\)
- B \(6.626\times10^{-38}\, m\)
- C \(6.626\times10^{-31}\, m\)
- D \(6.626\times10^{-30}\, m\)
Answer & Solution
Correct Answer
(B) \(6.626\times10^{-38}\, m\)
Step-by-step Solution
Detailed explanation
\(\lambda = \frac{h}{{mv}}\) \(h = 6.6 \times {10^{ - 34}}\,J - s\) \(m = 1000\,kg\) \(v = 36\,km/hr = \frac{{36 \times {{10}^3}}}{{60 \times 60}}\,m/\sec = 10\,m/\sec \) \(\lambda = \frac{{6.6 \times {{10}^{ - 34}}}}{{{{10}^3} \times 10}} = 6.6 \times {10^{ - 38}}\,m\)
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