JEE Mains · Chemistry · STD 11 - 7. Redox reactions
The correct order of the oxidation states of nitrogen in \(NO, N_2O, NO_2\) and \(N_2O_3\) is
- A \(N_2O < N_2O_3 < NO < NO_2\)
- B \(NO_2 < NO < N_2O_3 < N_2O\)
- C \(NO_2 < N_2O_3 < NO < N_2O\)
- D \(N_2O < NO < N_2O_3 < NO_2\)
Answer & Solution
Correct Answer
(D) \(N_2O < NO < N_2O_3 < NO_2\)
Step-by-step Solution
Detailed explanation
\(\mathop {NO}\limits^{ + 2} ,{\mkern 1mu} \mathop {{N_2}}\limits^{ + 1} O{\mkern 1mu} ,{\mkern 1mu} \mathop {{\text{ }}N}\limits^{ + 4} {O_2},\mathop {{N_2}}\limits^{ + 3} {O_3}\)
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