JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
For the reaction, \(aA + bB \rightarrow cC + dD ,\) the plot of log \(k\) vs \(\frac{1}{ T }\) is given below The temperature at which the rate constant of the reaction is \(10^{-4} s ^{-1}\) is .............. \(K\). (Rounded-off to the nearest integer) [Given: The rate constant of the reaction is \(10^{-5} s ^{-1}\) at \(500 K\).]

- A \(500\)
- B \(526\)
- C \(426\)
- D \(486\)
Answer & Solution
Correct Answer
(B) \(526\)
Step-by-step Solution
Detailed explanation
\(\log K =\log A -\frac{ Ea }{2.303 RT }\) \(\mid\)Slope\(\mid=\frac{E a}{2.303 R }=10,000\) \(\log \left(\frac{ K _{2}}{ K _{1}}\right)=\frac{ Ea }{2.303 R }\left(\frac{1}{ T _{1}}-\frac{1}{ T _{2}}\right)\)…
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