JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
Thermal decomposition of a \(Mn\) compound \((X)\) at \(513\, K\) results in compound \(Y\), \(MnO_2\) and a gaseous product. \(MnO_2\) reacts with \(NaCl\) and concentrated \(H_2SO_4\) to give a pungent gas \(Z. X, Y\) and \(Z\), respectively
- A \(K_2MnO_4, KMnO_4\) and \(SO_2\)
- B \(K_3MnO_4, K_2MnO_4\) and \(Cl_2\)
- C \(K_2MnO_4, KMnO_4\) and \(Cl_2\)
- D \(KMnO_4, K_2MnO_4\) and \(Cl_2\)
Answer & Solution
Correct Answer
(D) \(KMnO_4, K_2MnO_4\) and \(Cl_2\)
Step-by-step Solution
Detailed explanation
\(\mathop {2KMn{O_4}\,}\limits_{(X)} \xrightarrow[\Delta ]{{513\,\,K}}\,\mathop {{K_2}Mn{O_4}}\limits_{(Y)} \, + \,Mn{O_2}\, + {O_{2(g)}}\) \(Mn{O_2}\, + \,4NaCl\, + 4{H_2}S{O_4}\, \to \)…
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