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JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
The correct order of spin-only magnetic moments among the following is: (Atomic number: \(Mn\, = 25, Co\, = 27, Ni\, = 28, Zn\, = 30\))
- A \({\left[ {ZnC{l_4}} \right]^{2 - }} > {\left[ {NiC{l_4}} \right]^{2 - }} > {\left[ {CoC{l_4}} \right]^{2 - }} > {\left[ {MnC{l_4}} \right]^{2 - }}\)
- B \({\left[ {CoC{l_4}} \right]^{2 - }} > {\left[ {MnC{l_4}} \right]^{2 - }} > {\left[ {NiC{l_4}} \right]^{2 - }} > {\left[ {ZnC{l_4}} \right]^{2 - }}\)
- C \({\left[ {NiC{l_4}} \right]^{2 - }} > {\left[ {CoC{l_4}} \right]^{2 - }} > {\left[ {MnC{l_4}} \right]^{2 - }} > {\left[ {ZnC{l_4}} \right]^{2 - }}\)
- D \({\left[ {MnC{l_4}} \right]^{2 - }} > {\left[ {CoC{l_4}} \right]^{2 - }} > {\left[ {NiC{l_4}} \right]^{2 - }} > {\left[ {ZnC{l_4}} \right]^{2 - }}\)
Answer & Solution
Correct Answer
(D) \({\left[ {MnC{l_4}} \right]^{2 - }} > {\left[ {CoC{l_4}} \right]^{2 - }} > {\left[ {NiC{l_4}} \right]^{2 - }} > {\left[ {ZnC{l_4}} \right]^{2 - }}\)
Step-by-step Solution
Detailed explanation
The complex having higher number of unpaired electrons will have higher value of spin only magnetic moment. In all these complexes, the central metal ion is in \(+2\) oxidation state. \(Zn^{2+}\) has \(3d^{10}\) outer electronic configuration with \(0\) unpaired electron.…
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