JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
The correct combination is
- A \([NiCl_4]^{2-} -\) square-planar; \([Ni(CN)_4]^{2-} -\) paramagnetic
- B \([Ni( CN)_4]^{2-} -\) tetrahedral; \([Ni(CO)_4] -\) paramagnetic
- C \([NiCl_4]^{2-} -\) paramagnetic; \([Ni(CO)_4] -\) tetrahedral
- D \([NiCl_4]^{2-} -\) dimagnetic; \([Ni(CO)_4] -\) squareplanar
Answer & Solution
Correct Answer
(C) \([NiCl_4]^{2-} -\) paramagnetic; \([Ni(CO)_4] -\) tetrahedral
Step-by-step Solution
Detailed explanation
\([Ni(CN)]^{2-}\) is square planar, diamagnetic (\(0\) unpaired electrons) with \(dsp^2\) hybridisation.\([Ni(CO)_4] -\) is tetrahedral,diamagnetic (\(0\) unpaired electrons) with \(sp^3\) hybridisation. \([NiCl_4]^{2-}\) is tetrahedral, paramagnetic (\(2\) unpaired electrons)…
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