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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2018
  • Hard
  • MCQ

A heating element has a resistance of  \(100\,\Omega \) at room temperature. When it is connected to a supply of  \(220\,V,\)  a steady current of \(2\,A\)  passes in it and temperature is \(500\,^oC\) more than room temperature. What is the temperature coefficient resistance of the heating element?

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Answer & Solution

Correct Answer

(C) \(2\, \times \,{10^{ - {4}}}\,\,{^oC^{ - 1}}\)

Step-by-step Solution

Detailed explanation

Resistance after temperature increases by  \(500\,{\,^o}C\,\,i.e.,\,{R_t}\, = \,\frac{V}{I}\, = \frac{{220}}{2}\, = 110\,\Omega \)  \(R_0 = 100\) (given) temperature coefficient of resistance, \(\alpha  = ?\) 

using \(R_t = R_0( 1 + \alpha t)\)

\(110 = 100 (1 + \alpha 500)\)

\(\alpha \, = \,\frac{{10}}{{100 \times 500}}\)  or, \(\alpha \, = \,2 \times {10^{ - 4}}\,\,{^o C^{ - 1}}\)

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