JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
The anodic half-cell of lead-acid battery is recharged using electricity of \(0.05\, Faraday\). The amount of \(PbSO_4\) electrolyzed in \(g\) during the process is (Molar mass of \(PbSO_4 = 303\, g\, mol^{-1}\))
- A \(22.8\)
- B \(15.2\)
- C \(7.6\)
- D \(11.4\)
Answer & Solution
Correct Answer
(C) \(7.6\)
Step-by-step Solution
Detailed explanation
\(Pb\,(s)\, + \,SO_4^{2 - }\, \to \,PbS{O_4}\, + \,2{e^ - }\) For \(2\,F\) current passed, \(PdSO_4\) deposited \(=\,303\,g/mol\) For \(0.05\,F\) \(:\,PdSO_4\) deposited \( = \,\frac{{0.05\, \times \,303}}{2}\, = \,7.6\,g\)
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