JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The amount of arsenic pentasulphide that can be obtained when \(35.5\,g\) arsenic acid is treated with excess \(H_2S\) in the presence of cone. \(HCl\) (assuming \(100\%\) conversion) is \(....\,\,mol\)
- A \(0.25\)
- B \(0.50\)
- C \(0.333\)
- D \(0.125\)
Answer & Solution
Correct Answer
(D) \(0.125\)
Step-by-step Solution
Detailed explanation
\(\underset{1\,moles}{\mathop{\underset{2\,moles\,}{\mathop{2{{H}_{3}}As{{O}_{4}}}}\,}}\,+5{{H}_{2}}S\xrightarrow{Conc.HCl}\underset{1/2\,moles}{\mathop{\underset{1\,mole}{\mathop{A{{s}_{2}}{{S}_{5}}}}\,}}\,+8{{H}_{2}}O\) \(\therefore \) number of moles of \(H_3AsO_4\)…
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