JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
The osmotic pressure of blood is \(7.47\, bar\) at \(300\, K\). To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in \(g\,L ^{-1}\) is \(......\) (Molar mass of glucose \(=180 \,g\, mol ^{-1}\) \(R =0.083\, L\) bar \(K ^{-1} \,mol ^{-1}\) ) (Nearest integer)
- A \(11\)
- B \(33\)
- C \(54\)
- D \(44\)
Answer & Solution
Correct Answer
(C) \(54\)
Step-by-step Solution
Detailed explanation
\(\pi= C.R.T\) \(7.47= C \times 0.083 \times 300\) \(C =0.3 M\) \(=0.3 \times 180 gL ^{-1}\) \(=54 gL ^{-1}\)
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