ExamBro
ExamBro
JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

\(4.5 \,g\) of compound \(A ( MW =90)\) was used to make \(250\, mL\) of its aqueous solution. The molarity of the solution in \(M\) is \(x \times 10^{-1}\). The value of \(x\) is ............ (Rounded off to the nearest integer)

  1. A \(1\)
  2. B \(2\)
  3. C \(3\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(M =\frac{4.5 / 90}{250 / 1000}=0.2\) \(=2 \times 10^{-1}\)
From JEE Mains
Explore more questions on app