JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
\(4.5 \,g\) of compound \(A ( MW =90)\) was used to make \(250\, mL\) of its aqueous solution. The molarity of the solution in \(M\) is \(x \times 10^{-1}\). The value of \(x\) is ............ (Rounded off to the nearest integer)
- A \(1\)
- B \(2\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\(M =\frac{4.5 / 90}{250 / 1000}=0.2\) \(=2 \times 10^{-1}\)
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