JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization
\(R_f\) value for \(2\)-methylpropene in a solvent system (Ethyl acetate + ether) is \(0.42\). \(2\)-methylpropene is treated with dilute \(\text{H}_2\text{SO}_4\) to give major organic product (X). \(R_f\) value for (X) in the same solvent system under identical condition will be:
- A \(0.42\)
- B \(0.82\)
- C \(0.62\)
- D \(0.12\)
Answer & Solution
Correct Answer
(D) \(0.12\)
Step-by-step Solution
Detailed explanation
\(2\)-methylpropene reacts with dilute \(H_2SO_4\) to undergo hydration, forming tert-butyl alcohol as the major product (X). The reaction is: \(CH_2=C(CH_3)_2 \xrightarrow{\text{dil. } H_2SO_4} (CH_3)_3C-OH\) Product (X) is an alcohol, which is significantly more polar than the…
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