JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
Molality of \(0.8 \ \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4\) solution (density \(1.06 \mathrm{~g} \mathrm{~cm}^{-3}\) ) is _______ \(\times 10^{-3} m\).
- A \(814\)
- B \(817\)
- C \(816\)
- D \(815\)
Answer & Solution
Correct Answer
(D) \(815\)
Step-by-step Solution
Detailed explanation
\( \mathrm{m}=\frac{\mathrm{M} \times 1000}{\mathrm{~d}_{\text {sol }} \times 1000-\mathrm{M} \times \mathrm{Molar}^2 \text { mass }_{\text {solute }}} \) \( 815 \times 10^{-3} \mathrm{~m} \)
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