JEE Mains · Physics · STD 12 -7. Alternating current
An oscillating \(LC\) circuit consists of a \(75\,mH\) inductor and a \(1.2\,\mu F\) capacitor. If the maximum charge to the capacitor is \(2.7\,\mu C\). The maximum current in the circuit will be \(...........\,mA\).
- A \(8\)
- B \(9\)
- C \(6\)
- D \(5\)
Answer & Solution
Correct Answer
(B) \(9\)
Step-by-step Solution
Detailed explanation
Maximum energy stored in capacitor is same as maximum energy stored in inductor. \(\frac{1}{2} Li _{\max }^2=\frac{1}{2} \frac{ Q _{\max }^2}{ C }\) \(i _{\max }=\sqrt{\frac{1}{ LC }} Q _{\max }\)…
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