JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
Molality of an aqueous solution of urea is \(4.44 \mathrm{~m}\). Mole fraction of urea in solution is \(x \times 10^{-3}\). Value of \(x\) is _______. (integer answer)
- A \(70\)
- B \(73\)
- C \(74\)
- D \(80\)
Answer & Solution
Correct Answer
(C) \(74\)
Step-by-step Solution
Detailed explanation
Molality of urea is \(4.44 \mathrm{~m}\), that means \(4.44\) moles of urea present in \(1000 \mathrm{gm}\) of water. \(\therefore \mathrm{X}_{\text {urea }}=\frac{4.44}{4.44+\frac{1000}{18}}\) \(=0.0740\) \(74 \times 10^{-3}\) \(\mathrm{X}=74\)
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