JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
At \(300\, K\) and \(1\, atm,\, 15\, mL\) of a gaseous hydrocarbon requires \(375\, mL\) air containing \(20\%\,\, O_2\) by volume for complete combustion. After combustion the gases occupy \(330\, mL.\) Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is :
- A \(C_4H_8\)
- B \(C_4H_{10}\)
- C \(C_3H_6\)
- D \(C_3H_8\)
Answer & Solution
Correct Answer
(D) \(C_3H_8\)
Step-by-step Solution
Detailed explanation
\(C_{x} H_{y(g)}+\left(\frac{4 x+y}{4}\right) O_{2(g)} \rightarrow x C O_{2(g)}+\frac{y}{2} H_{2} O(l)\) Volume of \(O_{2}\) used \(=375 \times \frac{20}{100}=75 m l\) From the reaction of combination \(m l C_{x} H_{y}\) requires \(=\frac{4 x+y}{4} m l O_{2}\)…
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