JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry

Match List \(I\) with List \(II\)
\(LIST-I\) \((Substances)\) \(LIST-II\) \((Element Present)\)
\(A\). Ziegler catalyst \(I\). Rhodium
\(B\). Blood pigment \(II\). Cobalt
\(C\) .Wilkinson catalyst \(III\). Iron
\(D\). Vitamin \(\mathrm{B}_{12}\) \(IV\). Titanium
Choose the correct answer from the options given below:

A \(A-II\), \(B-IV\), \(C-I\), \(D-III\)
B \(A-II\), \(B-III\), \(C-IV\), \(D-I\)
C \(A-III\), \(B-II\), \(C-IV\), \(D-I\)
D \(A-IV\), \(B-III\), \(C-I\), \(D-II\)

Verified Solution

Answer & Solution

Correct Answer

(D) \(A-IV\), \(B-III\), \(C-I\), \(D-II\)

Step-by-step Solution

Detailed explanation

Ziegler catalyst \(\rightarrow\) Titanium Blood pigment \(\rightarrow\) Iron Wilkinson catalyst \(\rightarrow\) Rhodium Vitamin \(\mathrm{B}_{12} \rightarrow\) Cobalt

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match items of column \(I\) and \(II\)

Column \(I\) (Mixture of compounds)	Column \(II\) (Separation Technique)
\(A\) \(H _2 O / CH _2 Cl _2\)	\(I\) Crystallization
\(B\) \(Image\)	\(II\) Differential solvent extraction
\(C\) Kerosene/Naphthalene	\(III\) Column chromatography
\(D\) \(C _6 H _{12} O _6 / NaCl\)	\(IV\) Fractional Distillation

Correct match is :

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\(LIST-I\) \((Substances)\)	\(LIST-II\) \((Element Present)\)
\(A\). Ziegler catalyst	\(I\). Rhodium
\(B\). Blood pigment	\(II\). Cobalt
\(C\) .Wilkinson catalyst	\(III\). Iron
\(D\). Vitamin \(\mathrm{B}_{12}\)	\(IV\). Titanium